-16x^2+16x=-380

Solution for -16x^2+16x=-380 equation:

-16x^2+16x=-380

We move all terms to the left:

-16x^2+16x-(-380)=0

We add all the numbers together, and all the variables

-16x^2+16x+380=0

a = -16; b = 16; c = +380;
Δ = b2-4ac
Δ = 162-4·(-16)·380
Δ = 24576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24576}=\sqrt{4096*6}=\sqrt{4096}*\sqrt{6}=64\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-64\sqrt{6}}{2*-16}=\frac{-16-64\sqrt{6}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+64\sqrt{6}}{2*-16}=\frac{-16+64\sqrt{6}}{-32}
$